What is the force needed to push 35 kg to the top of the plane?

A frictionless incline plane is 6.5m long with the upper end 3.2m higher than the lower end. Acceleration is 9.8 m/s2. What is the force needed to push 35 kg to the top of the plane?What is the force needed to push 35 kg to the top of the plane?Alternative (easier) method:

Work done by applied force will be equal to gain in gravitational potential energy.

W=Fd

Ep=mgh

Fd=mgh

F=mgh/d

F= 35 * 9.8 * 3.2 / 6.5 = 169 NWhat is the force needed to push 35 kg to the top of the plane?first we will need to find out the angle of the incline.

This will be given by --%26gt; sin x = 3.2/6.5

--%26gt; x= 29.49 degrees



Now taking the sum of the forces along the inclined plane

--%26gt; F = m*g*sin x

--%26gt; F= 35*9.8* sin 29.49

--%26gt; F= 168.86 N