Two planes pass over Topeka at the same time, traveling in opposite directions. The rate of the faster plane is 20 mph greater than the slower plane. After 4 hours the planes are 800 miles apart. What is the speed of the faster plane?
Find two ways to solve it.
Thanks!What is the speed of the faster plane?let x = speed of faster plane
let x-20 = speed of slower plane
4(x) + 4(x-20) = 800
4x + 4x - 80 = 800
8x = 880
x = 110 mph
or...
let x = speed of slower plane
let x+20 = speed of faster plane
4(x) + 4(x+20) = 800
4x + 4x + 80 = 800
8x = 720
x = 90 mph
x+20 = 110 mph
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