A plane travels with n airspeed of 600 km/h to the south and descends at an angle of 18 degrees with the horizontal. A horizontal wind blows toward the east at 50 km/h. Find the resultant velocity of the plane.What is the resultant velocity of this plane?600cos(18) = 570.63 km/h relative to ground speed
tan^-1(50/570.63) = 5 degrees
570.63/cos(5) = 572.82 km/hWhat is the resultant velocity of this plane?If you add the two vectors, 600 S and 50 E, they add up to
R = √(6002 + 502) = 602 km/hour
angle is arctan 50/600 = 4.8 degrees, E of S
descending rate is not relevant.
,What is the resultant velocity of this plane?I'm afraid the descent rate is relevant.
If the airspeed is 600 kph, while descending at an angle of 18?, then the ground
speed is 600 . cos 18 = 570.6 kph.
The horizontal wind combines with this speed to produce the resultant ground velocity of
√ 570.6^2 + 50^2 = 572.8 kph (at S 05.00? E )
This component couples with the downward speed of 600 . sin 18 = 185.5 kph
to produce a final velocity of 602 kph at S 05? E , 18? down to the horizontal.
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